x+42/3+-0.67x^2=0

Solution for x+42/3+-0.67x^2=0 equation:

x+42/3+-0.67x^2=0

We add all the numbers together, and all the variables

-0.67x^2+x=0

a = -0.67; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-0.67)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-0.67}=\frac{-2}{-1.34}
=1+0.66/1.34
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-0.67}=\frac{0}{-1.34}
=0
$